Say that we have a binary search tree with the keys 1, 2, 3, 4, 5, 6, 7. A preorder traversal of the tree prints the keys in the sequence 4, 1, 3, 2, 6, 5, 7. What sequence would be printed by a postorder traversal of the tree?
Question
Say that we have a binary search tree with the keys 1, 2, 3, 4, 5, 6, 7. A preorder traversal of the tree prints the keys in the sequence 4, 1, 3, 2, 6, 5, 7. What sequence would be printed by a postorder traversal of the tree?
Solution
To determine the postorder traversal of the tree, we first need to understand the structure of the tree based on the given preorder traversal.
Preorder traversal visits nodes in the order Root, Left, Right. So, in our case, the root of the tree is 4. The keys less than 4 (1, 2, 3) are on the left subtree and the keys greater than 4 (5, 6, 7) are on the right subtree.
The left subtree, based on the preorder traversal (1, 3, 2), has 1 as the root, 2 as the right child of 3, and 3 as the right child of 1.
The right subtree, based on the preorder traversal (6, 5, 7), has 6 as the root, 5 as the left child of 6, and 7 as the right child of 6.
So, the tree looks like this:
4
/ \
1 6
\ / \
3 5 7
/
2
Postorder traversal visits nodes in the order Left, Right, Root. So, the postorder traversal of this tree would be 2, 3, 1, 5, 7, 6, 4.
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