Suppose the numbers 7, 5, 1, 8, 3, 6, 0, 9, 4, 2 are inserted in that order into an initially empty binary search tree. The binary search tree uses the usual ordering on natural numbers. What is the in-order traversal sequence of the resultant tree?
Question
Suppose the numbers 7, 5, 1, 8, 3, 6, 0, 9, 4, 2 are inserted in that order into an initially empty binary search tree. The binary search tree uses the usual ordering on natural numbers. What is the in-order traversal sequence of the resultant tree?
Solution
The in-order traversal of a binary search tree involves visiting the nodes in ascending order. This means we visit the left child, then the parent, and finally the right child.
Given the sequence 7, 5, 1, 8, 3, 6, 0, 9, 4, 2, the binary search tree would look like this:
7
/ \
5 8
/ \ \
1 6 9
/ \ / /
0 3 4 2
So, the in-order traversal sequence of the resultant tree would be: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
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