Let Y = yellow and y = green, and R = round and r = wrinkled. You cross YYRR peas with yyrr peas. All of the F1 individuals are yellow and round with a genotype of YyRr. You then perform an F2 cross and get the expected 9:3:3:1 phenotypic ratio. What proportion of the F2 plants are expected to be heterozygous for both traits?Multiple Choice1/161/49/161/2
Question
Let Y = yellow and y = green, and R = round and r = wrinkled. You cross YYRR peas with yyrr peas. All of the F1 individuals are yellow and round with a genotype of YyRr. You then perform an F2 cross and get the expected 9:3:3:1 phenotypic ratio. What proportion of the F2 plants are expected to be heterozygous for both traits?Multiple Choice1/161/49/161/2
Solution
The proportion of the F2 plants that are expected to be heterozygous for both traits is 4/16 or 1/4.
Here's the step-by-step explanation:
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The F1 cross between YYRR (yellow, round) and yyrr (green, wrinkled) results in all offspring being YyRr (yellow, round). This is because Y (yellow) and R (round) are dominant traits.
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When you perform an F2 cross (YyRr x YyRr), you get a 9:3:3:1 phenotypic ratio. This ratio represents the following phenotypes: 9/16 are yellow and round (YYRR, YYRr, YyRR, YyRr), 3/16 are yellow and wrinkled (YYrr, Yyrr), 3/16 are green and round (yyRR, yyRr), and 1/16 are green and wrinkled (yyrr).
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To find the proportion that are heterozygous for both traits (YyRr), we need to look at the 9/16 that are yellow and round. Of these, only 4/16 are YyRr.
So, the answer is 1/4.
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