Two pea plants are crossed. 50% percent of the offspring have seeds with a wrinkled appearance (caused by the presence of a homozygous recessive gene). What were the genotypes of the parents?Group of answer choicesRR x rrRr x rrRr x RrRR x Rr

Determine the percentage of the pea plant offspring from this genetic cross that are likely to have the Ff genotype like their parents.25%50%75%100%I'm not sure

are subsequently germinated. How many seedlings would have non-parental phenotype?heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross(b) All will exhibit recessive phenotype.(c) Dominant and recessive phenotypes will be 50% each.(d) Dominant phenotype will be 75%.(ii) If 'A' represents the dominant gene and 'a' represents its recessive allele, which of(i) In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plan

If you cross RrYy and RRyy pea plants, what fraction of the offspring will have round peas? R=round, r=wrinkled, Y=yellow, y=greenMultiple Choice50%75%100%25%0%

In the garden peas of one pair of alleles controls the height of theplant and a second pair of alleles controls flower colour. Theallele for tall (T) is dominant to the allele for dwarf (t) and theallele for purple flower colour (P) is dominant to the allele forwhite (p).a. A tall plant with purple flowers crossed with a dwarf plant withwhite flowers produced 50% tall, purple and 50% tall, whiteprogeny. What is the genotype of the parents?b. A tall plant with white flowers crossed with a dwarf plant withpurple flowers produced 25% tall purple, 25% tall white, 25%dwarf purple and 25% dwarf white individuals. What is thegenotype of the parents?

When a true-breeding pea plant that produces yellow round seeds (YYRR) is crossed with a true-breeding pea plant that produces green wrinkled seeds (yyrr), all of the F1 offspring produce yellow round seeds.  What fraction of the offspring of a F1 X F1 cross is predicted to produce green round seeds?  Group of answer choices