are subsequently germinated. How many seedlings would have non-parental phenotype?heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross(b) All will exhibit recessive phenotype.(c) Dominant and recessive phenotypes will be 50% each.(d) Dominant phenotype will be 75%.(ii) If 'A' represents the dominant gene and 'a' represents its recessive allele, which of(i) In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plan
Question
are subsequently germinated. How many seedlings would have non-parental phenotype?heterozygous for round shape of seed is selfed and 1600 seeds produced during the cross(b) All will exhibit recessive phenotype.(c) Dominant and recessive phenotypes will be 50% each.(d) Dominant phenotype will be 75%.(ii) If 'A' represents the dominant gene and 'a' represents its recessive allele, which of(i) In garden pea, round shape of seeds is dominant over wrinkled shape. A pea plan
Solution
It seems like your question got cut off. However, I can provide some information based on what you've given.
(i) If a heterozygous pea plant (Rr) for round shape of seed is selfed, the phenotypic ratio would be 3:1, according to Mendel's law of segregation. This means that out of 1600 seeds, 1200 (75%) would exhibit the dominant phenotype (round) and 400 (25%) would exhibit the recessive phenotype (wrinkled).
(ii) If 'A' represents the dominant gene and 'a' represents its recessive allele, the possible combinations could be 'AA' (homozygous dominant), 'Aa' (heterozygous), and 'aa' (homozygous recessive). The phenotype would depend on the specific traits that 'A' and 'a' represent. For example, if 'A' represents round seeds and 'a' represents wrinkled seeds, 'AA' and 'Aa' would result in round seeds, while 'aa' would result in wrinkled seeds.
Please provide the complete question for a more accurate answer.
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