What are the oxidation numbers of manganese in the following equation?KMnO4 → K2MnO4 + MnO4 + O2*from +7 to +6 to +4 it undergoes reductionfrom 0 to +2 to +3 it undergoes oxidationfrom 0 to +5 to -4 it undergoes both oxidation and reductionfrom +6 to -4 to +7 it undergoes both oxidation and reduction
Question
What are the oxidation numbers of manganese in the following equation?KMnO4 → K2MnO4 + MnO4 + O2*from +7 to +6 to +4 it undergoes reductionfrom 0 to +2 to +3 it undergoes oxidationfrom 0 to +5 to -4 it undergoes both oxidation and reductionfrom +6 to -4 to +7 it undergoes both oxidation and reduction
Solution
The oxidation numbers of manganese in the given equation are as follows:
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In KMnO4, the oxidation number of manganese is +7. This is because the oxidation number of K is +1 and that of O is -2. Since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of Mn is +7.
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In K2MnO4, the oxidation number of manganese is +6. This is because the oxidation number of K is +1 and that of O is -2. Since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of Mn is +6.
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In MnO4, the oxidation number of manganese is +7. This is because the oxidation number of O is -2. Since the compound is neutral, the sum of the oxidation numbers must be zero. Therefore, the oxidation number of Mn is +7.
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In O2, the oxidation number of manganese is not applicable as there is no manganese in O2.
So, the oxidation number of manganese changes from +7 in KMnO4 to +6 in K2MnO4 and back to +7 in MnO4. This means that manganese undergoes both oxidation and reduction in this reaction.
Similar Questions
In which compound does manganese have a +6 oxidation number?A.MnOB.MnO2C.K2MnO4D.KMnO4
State the oxidation state of manganese in KMnO4
In neutral or faintly alkaline medium KMnO4 being a powerful oxidant can oxidize, thiosulphate almost quantitatively, to sulphate. In this reaction overall change in oxidation state of manganese will be:
Potassium manganate(VII) reacts with potassium iodide. The change in oxidation number of manganese is from +7 to +2. What change has occurred to the iodide ions?
. Which statement accurately explains the reaction below?Fe2+(aq) + MnO4-(aq) → Fe3+(aq) + Mn2+(aq)Manganese is oxidized from a +7 oxidation state to a +2 oxidation state.Manganese is reduced from a +7 oxidation state to a +2 oxidation state.Manganese is oxidized from a +4 oxidation state to a +2 oxidation state.Manganese is reduced from a +4 oxidation state to a +2 oxidation state.
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