Potassium manganate(VII) reacts with potassium iodide. The change in oxidation number of manganese is from +7 to +2. What change has occurred to the iodide ions?
Question
Potassium manganate(VII) reacts with potassium iodide. The change in oxidation number of manganese is from +7 to +2. What change has occurred to the iodide ions?
Solution
In the reaction between potassium manganate(VII) and potassium iodide, the iodide ions are oxidized. This means that the oxidation number of iodine increases.
The oxidation number of iodine in iodide ions (I-) is -1. Since the manganese is reduced from +7 to +2 (a decrease of 5), the iodine must be oxidized by the same amount to maintain charge balance in the reaction.
Therefore, the oxidation number of iodine increases from -1 to +4. This is a change of +5, which matches the change in the manganese oxidation number.
So, the iodide ions have been oxidized in this reaction.
Similar Questions
What are the oxidation numbers of manganese in the following equation?KMnO4 → K2MnO4 + MnO4 + O2*from +7 to +6 to +4 it undergoes reductionfrom 0 to +2 to +3 it undergoes oxidationfrom 0 to +5 to -4 it undergoes both oxidation and reductionfrom +6 to -4 to +7 it undergoes both oxidation and reduction
In which compound does manganese have a +6 oxidation number?A.MnOB.MnO2C.K2MnO4D.KMnO4
State the oxidation state of manganese in KMnO4
In neutral or faintly alkaline medium KMnO4 being a powerful oxidant can oxidize, thiosulphate almost quantitatively, to sulphate. In this reaction overall change in oxidation state of manganese will be:
Potassium iodide (KI) contains potassium ions (K+) and iodide ions (I-).Describe what happens when an atom of potassium and iodine react to produce potassium iodide.Answer in terms of electrons.The iodine atom loses one electron to form a positive ion (I+). This electron is transferred to a potassium atom.The potassium atom gains one electron to form a negative ion (K-).The positive iodide ion and the negative potassium ion electrostatically attract, forming an ionic bond.The potassium ion loses one electron to form a positive ion (K+). This electron is transferred to an iodine atom.The iodine ion gains one electron to form a negative ion (I-).The positive potassium ion and the negative iodine ion electrostatically attract, forming an ionic bond.The potassium atom loses one electron to form a positive ion (K+). This electron is transferred to an iodine atom.The iodine atom gains one electron to form a negative ion (I-).The positive potassium ion and the negative iodide ion electrostatically attract, forming an ionic bond.The iodine atom loses one electron to form a negative ion (I-). This electron is transferred to a potassium atom.The potassium atom gains one electron to form a positive ion (K+).The positive potassium ion and the negative iodine ion electrostatically attract, forming an ionic bond.I DON'T KNOWSUBMIT ANSWER
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.