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In an examination 45% of students passed in math, 36% passed in English and 19% passed in both the subjects. What is the percentage of the students who failed in both the subjects?62%48%38%12%

Question

In an examination 45% of students passed in math, 36% passed in English and 19% passed in both the subjects. What is the percentage of the students who failed in both the subjects?62%48%38%12%

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Solution

To solve this problem, we first need to understand that the percentage of students who passed in both subjects is included in the percentage of students who passed in each subject.

Step 1: Add the percentage of students who passed in Math and English. 45% (Math) + 36% (English) = 81%

Step 2: Since the students who passed both subjects have been counted twice in the above calculation, we subtract the percentage of students who passed both subjects. 81% - 19% (Both) = 62%

So, 62% of students passed in either of the subjects or both.

Step 3: To find the percentage of students who failed in both subjects, we subtract the percentage of students who passed from 100%. 100% - 62% = 38%

So, 38% of students failed in both subjects. The correct answer is 38%.

This problem has been solved

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