In an examination, 36% of students failed in Science and 42% failed in Math while 20% failed in both the subjects. If the number of students who passed in only Math is 2800, then determine the total number of students who failed for either one or both subjects in the examination.(1 Point)5000890010150None of these
Question
In an examination, 36% of students failed in Science and 42% failed in Math while 20% failed in both the subjects. If the number of students who passed in only Math is 2800, then determine the total number of students who failed for either one or both subjects in the examination.(1 Point)5000890010150None of these
Solution
The problem can be solved using the principle of inclusion and exclusion.
First, we add the percentages of students who failed in Science and Math:
36% (Science) + 42% (Math) = 78%
However, we have double-counted the students who failed in both subjects, so we need to subtract this percentage:
78% - 20% (both) = 58%
This means that 58% of the students failed in either one or both subjects.
We know that the number of students who passed in only Math is 2800, which represents 42% - 20% = 22% of the total number of students.
So, if 22% is 2800 students, we can find out what 1% is:
2800 students / 22 = 127.27 students (approximately)
Now, we can find out the total number of students who failed in either one or both subjects:
58% * 127.27 students = 7383.66 students
Since we can't have a fraction of a student, we round this number to the nearest whole number, which is 7384 students.
So, the total number of students who failed in either one or both subjects is 7384. This option is not listed in the given choices, so the answer is "None of these".
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