Given a number x, reverse its binary form and return the answer in decimal.

Sure, here is a step-by-step solution in Python:

1. First, convert the given number to binary using the built-in bin() function. This function converts an integer number to a binary string prefixed with "0b".

x = 10
binary_x = bin(x)[2:]  # '1010'

2. Next, reverse the binary string using slicing.

reversed_binary = binary_x[::-1]  # '0101'

3. Finally, convert the reversed binary string back to an integer using the built-in int() function with base 2.

result = int(reversed_binary, 2)  # 5

So, the final Python code would look like this:

def reverse_binary(x):
    binary_x = bin(x)[2:]
    reversed_binary = binary_x[::-1]
    result = int(reversed_binary, 2)
    return result

You can call this function with a number as an argument to get the decimal number of the reversed binary form:

print(reverse_binary(10))  # Output: 5