Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Question
Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.
Solution
Sure, here is a Python solution for the problem:
def reverse(x):
sign = [1,-1][x < 0] # This will store the sign of the number
rev, x = 0, abs(x) # Reverse the number and take the absolute value of x
while x:
x, mod = divmod(x, 10) # Get the quotient and remainder of x / 10
rev = rev * 10 + mod # Construct the reversed number
if rev > 2**31-1: # Check if the reversed number is out of the 32-bit integer range
return 0
return sign*rev # Return the reversed number with its original sign
This function works by repeatedly taking the last digit of x and appending it to the reverse of the remaining digits. If at any point the reversed number exceeds 2**31-1, it returns 0. The sign of the original number is preserved.
Similar Questions
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