The distance of the point (a cos θ, a sinθ) from the origin is
Question
The distance of the point (a cos θ, a sinθ) from the origin is
Solution
To find the distance of the point (a cos θ, a sin θ) from the origin, we can use the distance formula.
The distance formula states that the distance between two points (x1, y1) and (x2, y2) in a two-dimensional plane is given by the formula:
d = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of the point are (a cos θ, a sin θ), and the coordinates of the origin are (0, 0).
Substituting these values into the distance formula, we get:
d = √((a cos θ - 0)^2 + (a sin θ - 0)^2)
Simplifying further, we have:
d = √(a^2 cos^2 θ + a^2 sin^2 θ)
Using the trigonometric identity cos^2 θ + sin^2 θ = 1, we can simplify the equation to:
d = √(a^2 (cos^2 θ + sin^2 θ))
Since cos^2 θ + sin^2 θ = 1, the equation becomes:
d = √(a^2)
Therefore, the distance of the point (a cos θ, a sin θ) from the origin is simply a.
Similar Questions
The distance between the points (sin , cos ) and (cos , – sin ) is
If and , then the cosine of the angle θ between the two vectors is:
Consider the graph of the polar function 𝑟=𝑓(𝜃), where 𝑓(𝜃)=1+2sin𝜃, in the polar coordinate system for 0≤𝜃≤2𝜋. Which of the following statements is true about the distance between the point with polar coordinates (𝑓(𝜃),𝜃) and the origin?
Given that sin θ = , then cos θ is
The _____ of a circle centered at the origin measures the distance from the origin to any point on the circle.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.