The distance between the points (sin , cos ) and (cos , – sin ) is
Question
The distance between the points (sin , cos ) and (cos , – sin ) is
Solution
The distance between two points in a plane is given by the formula:
d = sqrt[(x2 - x1)² + (y2 - y1)²]
Here, the points are (sin, cos) and (cos, -sin). Let's substitute these values into the formula:
d = sqrt[(cos - sin)² + (-sin - cos)²]
This simplifies to:
d = sqrt[(cos - sin)² + (-2sin)²]
d = sqrt[(cos² - 2sin*cos + sin²) + 4sin²]
Since sin² + cos² = 1 (from the Pythagorean identity), this further simplifies to:
d = sqrt[1 + 4sin² - 2sin*cos]
This is the distance between the points (sin, cos) and (cos, -sin).
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