What will be the output of the following C code?#include <stdio.h>void main(){int k = 5;int *p = &k;int **m = &p; **m = 6; printf("%d\n", k);}A. 5B. Run time errorC. 6D. Junk

The output of the given C code will be 6.

Here's the step by step explanation:

1. An integer variable k is declared and initialized with the value 5.
2. A pointer p is declared and it is initialized with the address of k.
3. A pointer to a pointer m is declared and it is initialized with the address of p.
4. The value at the address pointed to by m (which is the address pointed to by p, which is the address of k) is changed to 6. This effectively changes the value of k to 6.
5. The value of k is printed, which is now 6.

So, the correct answer is C. 6.