Write a function that prints a square with the character #.Prototype: def print_square(size):size is the size length of the squaresize must be an integer, otherwise raise a TypeError exception with the message size must be an integerif size is less than 0, raise a ValueError exception with the message size must be >= 0if size is a float and is less than 0, raise a TypeError exception with the message size must be an integerYou are not allowed to import any module

Sure! Here is a step-by-step solution to the problem:

1. Define the function print_square with a single parameter size.
2. Check if size is an integer using the isinstance() function. If it is not, raise a TypeError exception with the message "size must be an integer".
3. Check if size is less than 0. If it is, raise a ValueError exception with the message "size must be >= 0".
4. Check if size is a float using the isinstance() function. If it is, check if it is less than 0. If both conditions are true, raise a TypeError exception with the message "size must be an integer".
5. If all the checks pass, proceed to print the square.
6. Use a loop to iterate size times to print each row of the square.
7. Within the loop, use another loop to print size number of "#" characters to form each row of the square.
8. After printing each row, use the print() function with no arguments to move to the next line.
9. Test the function with different inputs to ensure it works correctly.

Here is the code implementation:

def print_square(size):
    if not isinstance(size, int):
        raise TypeError("size must be an integer")
    if size < 0:
        raise ValueError("size must be >= 0")
    if isinstance(size, float) and size < 0:
        raise TypeError("size must be an integer")

    for _ in range(size):
        print("#" * size)

# Testing the function
print_square(5)  # Prints a square of size 5x5
print_square(3)  # Prints a square of size 3x3
print_square(0)  # Prints an empty square

This function will print a square of "#" characters with the given size.