The following chemical reaction takes place in aqueous solution:ZnSO4(aq)+2NaOH(aq)→ZnOH2(s)+Na2SO4(aq)Write the net ionic equation for this reaction.

Sure, here are the steps to write the net ionic equation for the given reaction:

1. First, write down the balanced molecular equation:

   ZnSO4(aq) + 2NaOH(aq) → ZnOH2(s) + Na2SO4(aq)

2. Next, write the total ionic equation. This involves breaking all the aqueous substances into their ions:

   Zn2+(aq) + SO4^2-(aq) + 2Na+(aq) + 2OH-(aq) → ZnOH2(s) + 2Na+(aq) + SO4^2-(aq)

3. Now, you can write the net ionic equation by removing the spectator ions. Spectator ions are ions that appear on both sides of the equation. In this case, the spectator ions are Na+ and SO4^2-.

   The net ionic equation is:

   Zn2+(aq) + 2OH-(aq) → ZnOH2(s)

Sure, here are the steps to write the net ionic equation for the given reaction:

1. First, write down the balanced molecular equation: ZnSO4(aq) + 2NaOH(aq) → Zn(OH)2(s) + Na2SO4(aq)

2. Next, write the ionic equation by breaking all the aqueous substances into their ions: Zn2+(aq) + SO4^2-(aq) + 2Na+(aq) + 2OH-(aq) → Zn(OH)2(s) + 2Na+(aq) + SO4^2-(aq)

3. Now, identify and cancel out the spectator ions that appear on both sides of the equation. In this case, the spectator ions are Na+ and SO4^2-.

4. After cancelling out the spectator ions, you are left with the net ionic equation: Zn2+(aq) + 2OH-(aq) → Zn(OH)2(s)