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Which is the R command to estimate the model ๐‘Ÿ" =f$ +f& ๐‘Ÿ"'& +f( ๐‘Ÿ"'( +f) ๐‘Ÿ"') + ๐‘Ž" โˆ’q& ๐‘Ž"'& ? Suppose x is the time series ๐‘Ÿ" in the R command.a. arima(x,order=c(1,0,3))b. arima(x,order=c(3,1,0))c. arima(x,order=c(3,0,1))d. arima(x,order=c(0,1,3))

Question

Which is the R command to estimate the model ๐‘Ÿ" =f$ +f& ๐‘Ÿ"'& +f( ๐‘Ÿ"'( +f) ๐‘Ÿ"') + ๐‘Ž" โˆ’q& ๐‘Ž"'& ? Suppose x is the time series ๐‘Ÿ" in the R command.a. arima(x,order=c(1,0,3))b. arima(x,order=c(3,1,0))c. arima(x,order=c(3,0,1))d. arima(x,order=c(0,1,3))

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Solution

The correct answer is b. arima(x,order=c(3,1,0))

Here's why:

The ARIMA model is represented as ARIMA(p,d,q) where:

  • p is the order of the Autoregressive part
  • d is the order of the differencing involved
  • q is the order of the Moving average part

In the given model ๐‘Ÿ" =f$ +f& ๐‘Ÿ"'& +f( ๐‘Ÿ"'( +f) ๐‘Ÿ"') + ๐‘Ž" โˆ’q& ๐‘Ž"'&, we can see that:

  • There are 3 past values of the variable r (๐‘Ÿ"'&, ๐‘Ÿ"'(, ๐‘Ÿ"')), which means the order of the Autoregressive part (p) is 3.
  • The term ๐‘Ž" โˆ’q& ๐‘Ž"'& represents the difference between the current error term and the past error term, which means the order of differencing (d) is 1.
  • There is no moving average part in the model, which means the order of the Moving average part (q) is 0.

Therefore, the correct R command to estimate this model is arima(x,order=c(3,1,0)).

This problem has been solved

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