Which is the R command to estimate the model ๐" =f$ +f& ๐"'& +f( ๐"'( +f) ๐"') + ๐" โq& ๐"'& ? Suppose x is the time series ๐" in the R command.a. arima(x,order=c(1,0,3))b. arima(x,order=c(3,1,0))c. arima(x,order=c(3,0,1))d. arima(x,order=c(0,1,3))
Question
Which is the R command to estimate the model ๐" =f$ +f& ๐"'& +f( ๐"'( +f) ๐"') + ๐" โq& ๐"'& ? Suppose x is the time series ๐" in the R command.a. arima(x,order=c(1,0,3))b. arima(x,order=c(3,1,0))c. arima(x,order=c(3,0,1))d. arima(x,order=c(0,1,3))
Solution
The correct answer is b. arima(x,order=c(3,1,0))
Here's why:
The ARIMA model is represented as ARIMA(p,d,q) where:
- p is the order of the Autoregressive part
- d is the order of the differencing involved
- q is the order of the Moving average part
In the given model ๐" =f$ +f& ๐"'& +f( ๐"'( +f) ๐"') + ๐" โq& ๐"'&, we can see that:
- There are 3 past values of the variable r (๐"'&, ๐"'(, ๐"')), which means the order of the Autoregressive part (p) is 3.
- The term ๐" โq& ๐"'& represents the difference between the current error term and the past error term, which means the order of differencing (d) is 1.
- There is no moving average part in the model, which means the order of the Moving average part (q) is 0.
Therefore, the correct R command to estimate this model is arima(x,order=c(3,1,0)).
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