What is the temperature change if 1400 J of heat is added to 4.80 g of solid beryllium to 1 d.p?(The molar heat capacity of solid beryllium is 16.4 J mol-1 K-1) Useful Formula...!q = c m ΔT
Question
What is the temperature change if 1400 J of heat is added to 4.80 g of solid beryllium to 1 d.p?(The molar heat capacity of solid beryllium is 16.4 J mol-1 K-1) Useful Formula...!q = c m ΔT
Solution
Sure, I can help with that. Here's how you can calculate it:
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First, we need to convert the mass of beryllium to moles. The molar mass of beryllium is about 9.012 g/mol. So, 4.80 g of beryllium is 4.80 g / 9.012 g/mol = 0.532 mol.
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Next, we can use the formula q = c m ΔT, where q is the heat added, c is the molar heat capacity, m is the mass in moles, and ΔT is the change in temperature. We're solving for ΔT, so we can rearrange the formula to get ΔT = q / (c m).
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Now we can plug in the values: ΔT = 1400 J / (16.4 J mol-1 K-1 * 0.532 mol) = 162.79 K.
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To 1 decimal place, the temperature change is 162.8 K.
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