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A car travelling on a straight road in the same direction covers half a distance at a uniform velocity of 80 km/h and the other half of the distance travelling uniformly at 40 km/h. What is the magnitude of average velocity over the total period of motion?

Question

A car travelling on a straight road in the same direction covers half a distance at a uniform velocity of 80 km/h and the other half of the distance travelling uniformly at 40 km/h. What is the magnitude of average velocity over the total period of motion?

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Solution

To solve this problem, we need to find the total distance covered, the total time taken, and then use these to calculate the average velocity.

Step 1: Let's assume the total distance covered is 2D (D for each half of the journey).

Step 2: The time taken to cover the first half of the journey (D) at 80 km/h is D/80 hours.

Step 3: The time taken to cover the second half of the journey (D) at 40 km/h is D/40 hours.

Step 4: The total time taken for the journey is the sum of the time taken for each half, which is D/80 + D/40 = 3D/80 hours.

Step 5: The average velocity is the total distance divided by the total time, which is 2D / (3D/80) = 160/3 km/h.

So, the magnitude of the average velocity over the total period of motion is 160/3 km/h or approximately 53.33 km/h.

This problem has been solved

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