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A car moving at a speed of 50 km/hr, returns on the same route with a speed of 40 km/hr. What is the average speed?

Question

A car moving at a speed of 50 km/hr, returns on the same route with a speed of 40 km/hr. What is the average speed?

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Solution

The average speed is calculated by the total distance traveled divided by the total time taken. In this case, the car travels the same distance twice (once going and once returning), so the total distance is 2d (where d is the distance).

The time taken for each leg of the journey is the distance divided by the speed. So, the time taken is d/50 + d/40.

Therefore, the average speed (v_avg) is given by:

v_avg = total distance / total time = 2d / (d/50 + d/40)

To simplify this, you can find a common denominator for the fractions in the denominator:

= 2d / [(40d + 50d) / (50*40)] = 2d / [90d / 2000] = 2d / (9d/200) = 2d * (200/9d) = 400/9 km/hr = 44.44 km/hr

So, the average speed of the car is approximately 44.44 km/hr.

This problem has been solved

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