The displacement current (Id) in a capacitor is given by the equation:

Id = ε * (dφE/dt)

Where:
ε is the permittivity of free space,
dφE/dt is the rate of change of electric flux.

However, in this case, we are given the reactance (Xc) of the capacitor and the resistance (R) in the circuit. We can use these values to find the total impedance (Z) of the circuit using the formula:

Z = sqrt(R^2 + Xc^2)

Substituting the given values:

Z = sqrt((100 Ω)^2 + (100 Ω)^2) = sqrt(20000) = 141.42 Ω

The peak current (I) in the circuit can be found using Ohm's law:

I = V/Z

Substituting the given values:

I = 220 V / 141.42 Ω = 1.56 A

The displacement current is equal to the current in the circuit when the capacitor is 50% charged. Therefore, the peak value of the displacement current is 1.56 A.

Question

The displacement current (Id) in a capacitor is given by the equation:

Id = ε * (dφE/dt)

Where:
ε is the permittivity of free space,
dφE/dt is the rate of change of electric flux.

However, in this case, we are given the reactance (Xc) of the capacitor and the resistance (R) in the circuit. We can use these values to find the total impedance (Z) of the circuit using the formula:

Z = sqrt(R^2 + Xc^2)

Substituting the given values:

Z = sqrt((100 Ω)^2 + (100 Ω)^2) = sqrt(20000) = 141.42 Ω

The peak current (I) in the circuit can be found using Ohm's law:

I = V/Z

Substituting the given values:

I = 220 V / 141.42 Ω = 1.56 A

The displacement current is equal to the current in the circuit when the capacitor is 50% charged. Therefore, the peak value of the displacement current is 1.56 A.

Knowee AI · Accepted Answer

The displacement current (Id) in a capacitor is given by the equation:

Id = ε * (dφE/dt)

Where:
ε is the permittivity of free space,
dφE/dt is the rate of change of electric flux.

However, in this case, we are given the reactance (Xc) of the capacitor and the resistance (R) in the circuit. We can use these values to find the total impedance (Z) of the circuit using the formula:

Z = sqrt(R^2 + Xc^2)

Substituting the given values:

Z = sqrt((100 Ω)^2 + (100 Ω)^2) = sqrt(20000) = 141.42 Ω

The peak current (I) in the circuit can be found using Ohm's law:

I = V/Z

Substituting the given values:

I = 220 V / 141.42 Ω = 1.56 A

The displacement current is equal to the current in the circuit when the capacitor is 50% charged. Therefore, the peak value of the displacement current is 1.56 A.

A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is

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