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Two point charges in air are 2 m apart.If one charge is three times the other, their mutual force is 2.7 Into ten to the power five dyne What is the value of each charg

Question

Two point charges in air are 2 m apart.If one charge is three times the other, their mutual force is 2.7 Into ten to the power five dyne What is the value of each charg

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Solution

The problem can be solved using Coulomb's Law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is:

F = k * |q1*q2| / r^2

where: F is the force between the charges, k is Coulomb's constant (9 * 10^9 N.m^2/C^2), q1 and q2 are the amounts of charge, r is the distance between the charges.

Given: F = 2.7 * 10^5 dyne (we need to convert this to Newton, 1 dyne = 10^-5 N, so F = 2.7 N), r = 2 m, q1 = 3q (where q is the smaller charge).

Substituting these values into the formula, we get:

2.7 = 9 * 10^9 * |3q*q| / 2^2

Solving this equation for q gives the value of the smaller charge. The larger charge is 3 times this value.

This problem has been solved

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