*Force Between ChargesTwo point charges experience an attractive force of 8 N when they are separated by 1 m. What is the magnitude of the force they experience when their separation is 0.5 m?
Question
*Force Between ChargesTwo point charges experience an attractive force of 8 N when they are separated by 1 m. What is the magnitude of the force they experience when their separation is 0.5 m?
Solution
The force between two point charges is given by Coulomb's law:
F = k * |q1*q2| / r^2
where F is the force, k is Coulomb's constant (approximately 8.99 x 10^9 N*m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
According to this equation, the force is inversely proportional to the square of the distance between the charges. This means that if the distance is halved (from 1 m to 0.5 m), the force will increase by a factor of (1/0.5)^2 = 4.
Therefore, if the initial force was 8 N, the force when the charges are 0.5 m apart will be 8 N * 4 = 32 N.
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