Zinc metal reacts with aqueous hydrochloric acid to produce zinc chloride and hydrogen gas. Zn (s) + 2 HCl (aq) → ZnCl2 (aq) + H2 (g) What volume of 3.55 M HCl is required to produce 25.5 L of hydrogen gas at a temperature of 298 K and a pressure of 1.20 atm?Group of answer choices1.25 L2.50 L0.705 L8.88 L
Question
Zinc metal reacts with aqueous hydrochloric acid to produce zinc chloride and hydrogen gas. Zn (s) + 2 HCl (aq) → ZnCl2 (aq) + H2 (g) What volume of 3.55 M HCl is required to produce 25.5 L of hydrogen gas at a temperature of 298 K and a pressure of 1.20 atm?Group of answer choices1.25 L2.50 L0.705 L8.88 L
Solution
To solve this problem, we need to use the ideal gas law and stoichiometry.
The ideal gas law is PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature.
First, we need to find the number of moles of hydrogen gas. We can rearrange the ideal gas law to solve for n: n = PV/RT.
Substituting the given values, we get n = (1.20 atm)(25.5 L) / (0.0821 L·atm/K·mol)(298 K) = 1.24 mol of H2.
From the balanced chemical equation, we know that 1 mol of Zn reacts with 2 mol of HCl to produce 1 mol of H2. Therefore, we need 2 * 1.24 mol = 2.48 mol of HCl.
The molarity of a solution is defined as the number of moles of solute per liter of solution. Therefore, the volume of HCl solution required is 2.48 mol / 3.55 M = 0.70 L.
So, the correct answer is 0.705 L.
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