What will be the output of the following C code?#include <stdio.h>int x = 0;void main(){int *const ptr = &x;printf("%p\n", ptr);ptr++;printf("%p\n ", ptr);} 0 1Compile time error0xbfd605e8 0xbfd605ec0xbfd605e8 0xbfd605e8Clear ResponseSave & Next

The output of the given C code will be a compile-time error. This is because the pointer 'ptr' is declared as a constant pointer to an integer. This means that the pointer itself cannot be modified, i.e., it cannot point to a different memory location once it is initialized. However, in the code, there is an attempt to increment the pointer 'ptr' using 'ptr++'. This is not allowed and will result in a compile-time error.