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The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm–1. Calculate specific conductance.

Question

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm–1. Calculate specific conductance.

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Solution

Sure, here's how you can calculate the specific conductance:

Step 1: Understand the formula The specific conductance (also known as conductivity) is calculated by the formula:

Specific conductance = 1 / (Resistance * Cell constant)

Step 2: Plug in the given values In this case, the resistance is 210 ohm and the cell constant is 0.88 cm–1. So, you can substitute these values into the formula:

Specific conductance = 1 / (210 ohm * 0.88 cm–1)

Step 3: Calculate After performing the calculation, you will get the specific conductance.

Please note that the unit of specific conductance is S cm-1 (Siemens per centimeter).

This problem has been solved

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