The cell constant of a conductivity cell is 0.146 cm-1. What is the conductivity of 0.01 M solutionof an electrolyte at 298 K, if the resistance of the cell is 1000 ohm?

The resistance of a 0.01 N solution of an electrolyte was found to 210 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm–1. Calculate specific conductance.

If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4 cm–1 then its molar conductance in ohm–1 cm2 mol–1 is :10 S cm2mol–1102 S cm2mol–1103 S cm2mol–1104 S cm2mol–1

Resistance of a conductivity cell (cell constant 129 m–1) filled with 74.5 ppm solution of KCl is 100  Ω (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is 50  Ω (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e.  ∧1∧2  =  x × 10−3. The value of x is______. (Nearest integer)Given, molar mass of KCl is 74.5 g mol–1.

Express the relation among cell constant, resistance of the solution in the cell and conductivity of the solution. How is molar conductivity of a solution related to its conductivity?

The molar conductivity of 0.1 M CH3COOH solution is 4 S cm2 mol–1. What is the resistivity of the solution ?2200 Ω cm2500 Ω cm2400 Ω cm2000 Ω cm