A car with a weight of 15,000N is being towed up a 20 degree slope at constant velocity. Friction is negligible. What is the net force in the x-component?Give you answer to 0 decimal places in N. Do not include the units in your answer i.e. you would write 100 N as 100.
Question
A car with a weight of 15,000N is being towed up a 20 degree slope at constant velocity. Friction is negligible. What is the net force in the x-component?Give you answer to 0 decimal places in N. Do not include the units in your answer i.e. you would write 100 N as 100.
Solution
The net force in the x-component can be calculated using the formula F = mgsin(θ), where m is the mass of the car, g is the acceleration due to gravity, and θ is the angle of the slope.
First, we need to find the mass of the car. We know that weight = mass * gravity. So, mass = weight / gravity = 15000N / 9.8m/s^2 = 1530.6 kg.
Next, we substitute the values into the formula:
F = 1530.6 kg * 9.8 m/s^2 * sin(20 degrees) = 5154.6 N.
Rounding to 0 decimal places, the net force in the x-component is 5155 N. So, the answer is 5155.
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