car is free-wheeling down a hill at constant velocity, which means that the resultant force which is acting on it is zero. The downhill component of its weight is equal to 10 kN, and the force of air resistance which is acting is equal to 6 kN. Calculate the total frictional force which is acting on the car. You may assume that no additional forces are acting on it.16 kN4 kN10 kN6 kN
Question
car is free-wheeling down a hill at constant velocity, which means that the resultant force which is acting on it is zero. The downhill component of its weight is equal to 10 kN, and the force of air resistance which is acting is equal to 6 kN. Calculate the total frictional force which is acting on the car. You may assume that no additional forces are acting on it.16 kN4 kN10 kN6 kN
Solution
The car is free-wheeling down a hill at a constant velocity, which means the net force acting on it is zero. This is due to Newton's first law of motion, which states that an object in motion will stay in motion with the same speed and direction unless acted upon by an unbalanced force.
Given:
- The downhill component of the car's weight is 10 kN.
- The force of air resistance acting on the car is 6 kN.
We are asked to find the total frictional force acting on the car.
Since the net force is zero, the sum of all forces acting on the car should be zero. This means that the sum of the downhill force and the air resistance should be equal to the frictional force.
So, we can set up the equation as follows:
Downhill force + Air resistance = Frictional force
Substituting the given values into the equation gives:
10 kN (downhill force) + 6 kN (air resistance) = Frictional force
Therefore, the total frictional force acting on the car is 16 kN.
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