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A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?Options5 litres, 7 litres7 litres, 4 liters6 litres, 6 liters4 litres, 8 liters

Question

A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?Options5 litres, 7 litres7 litres, 4 liters6 litres, 6 liters4 litres, 8 liters

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Solution

This problem can be solved using the concept of mixtures and alligations.

Let's denote the amount of milk from the first can as x and the amount of milk from the second can as 12 - x (since the total amount of milk is 12 litres).

The first can contains 75% milk and the second can contains 50% milk. The mixture should contain 5/8 (or 62.5%) milk because the ratio of water to milk is 3:5.

We can set up the following equation using the rule of alligation:

(75 - 62.5) / (62.5 - 50) = x / (12 - x)

Solving this equation gives x = 5.

Therefore, the milk vendor should mix 5 litres of milk from the first can and 7 litres of milk from the second can to get the desired ratio.

So, the correct option is 5 litres, 7 litres.

This problem has been solved

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