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log6−log3−log2

Question

log6−log3−log2

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Solution

The given expression is "log6 - log3 - log2".

This is a logarithmic expression and we can simplify it using the properties of logarithms.

Step 1: Apply the quotient rule of logarithms, which states that logb(m/n) = logb(m) - logb(n).

So, the expression becomes log(6/3) - log2.

Step 2: Simplify the fraction inside the first logarithm.

This gives us log(2) - log2.

Step 3: Apply the quotient rule of logarithms again.

This simplifies the expression to log(2/2).

Step 4: Simplify the fraction inside the logarithm.

This gives us log(1).

Step 5: Recall that logb(1) = 0 for any base b.

So, the final answer is 0.

This problem has been solved

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