log6−log3−log2
Solution
The given expression is "log6 - log3 - log2".
This is a logarithmic expression and we can simplify it using the properties of logarithms.
Step 1: Apply the quotient rule of logarithms, which states that logb(m/n) = logb(m) - logb(n).
So, the expression becomes log(6/3) - log2.
Step 2: Simplify the fraction inside the first logarithm.
This gives us log(2) - log2.
Step 3: Apply the quotient rule of logarithms again.
This simplifies the expression to log(2/2).
Step 4: Simplify the fraction inside the logarithm.
This gives us log(1).
Step 5: Recall that logb(1) = 0 for any base b.
So, the final answer is 0.
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