2log b​ 6−log b​ 2

I'm sorry, but you didn't provide a specific question. However, I can simplify the expression you've given using the properties of logarithms. Here's how:

The expression is: 2log_b(6) - log_b(2)

Step 1: Apply the power rule of logarithms which states that log_b(a^n) = n*log_b(a). So, 2log_b(6) becomes log_b(6^2) = log_b(36).

So, the expression now is: log_b(36) - log_b(2)

Step 2: Apply the quotient rule of logarithms which states that log_b(a) - log_b(c) = log_b(a/c). So, log_b(36) - log_b(2) becomes log_b(36/2) = log_b(18).

So, the simplified expression is: log_b(18)