What will be the output after the following statements?x = ["Yesterday's", "Today's", "Tomorrow's"] y = ['temperature'] for i in x: if i[0] != 'y': for j in y: print(j, end=' ')Optionstemperature temperaturetemperature temperature temperatureYesterday's Today's Tomorrow'stemperature
Question
What will be the output after the following statements?x = ["Yesterday's", "Today's", "Tomorrow's"] y = ['temperature'] for i in x: if i[0] != 'y': for j in y: print(j, end=' ')Optionstemperature temperaturetemperature temperature temperatureYesterday's Today's Tomorrow'stemperature
Solution
The output will be "temperature temperature temperature". Here's why:
- The variable
xis a list containing three strings: "Yesterday's", "Today's", "Tomorrow's". - The variable
yis a list containing one string: 'temperature'. - The
forloop iterates over each element in thexlist. - The
ifstatement checks if the first character of the current element inxis not 'y'. Since none of the elements inxstart with 'y' (Python is case-sensitive, so 'Y' is not the same as 'y'), the condition is always true. - For each element in
x, the innerforloop iterates over each element iny(which is just 'temperature') and prints it, followed by a space (due toend=' '). - Since there are three elements in
xand theifcondition is always true, 'temperature' is printed three times, each followed by a space.
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