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What will be the output of the following Python code?code = [[0, 1, 2, 9], [1, 10, 0, 18]]ct = code[0][0]for x in code:    for y in x:        if ct > y:            ct = yprint(ct)Options2109

Question

What will be the output of the following Python code?code = [[0, 1, 2, 9], [1, 10, 0, 18]]ct = code[0][0]for x in code:    for y in x:        if ct > y:            ct = yprint(ct)Options2109

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Solution

The output of the given Python code will be 0.

Here's the step by step explanation:

  1. The variable ct is initialized with the value of the first element of the first list in code, which is 0.
  2. The outer loop iterates over each list in code.
  3. The inner loop iterates over each element in the current list.
  4. The if statement checks if the current element y is less than ct.
  5. If y is less than ct, ct is updated to the value of y.
  6. This process continues until all elements in all lists have been checked.
  7. Finally, the value of ct is printed, which is the smallest value found in all the lists.

Since 0 is the smallest number in the lists and it's the initial value of ct, ct never changes. So, the output is 0.

This problem has been solved

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