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What will be the output of the following Python code?y=7def ct(m,n=y): print(m,n)y=9ct(5)OptionsError5 75 97 5

Question

What will be the output of the following Python code?y=7def ct(m,n=y): print(m,n)y=9ct(5)OptionsError5 75 97 5

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Solution

The output of the Python code will be "5 7".

Here's the step by step explanation:

  1. The variable y is initially set to 7.
  2. The function ct(m,n=y) is defined. Here, n is a default argument with a default value of y, which is 7 at the time of function definition.
  3. The variable y is then set to 9. However, this does not affect the default value of n in the function ct, because default argument values in Python are evaluated at the point of function definition in the defining scope.
  4. When the function ct is called with a single argument 5, m is set to 5 and n takes its default value, which is 7.
  5. The function ct prints m and n, so "5 7" is printed.

This problem has been solved

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