The output of the given Python code will be 10.

Here's the step by step explanation:

1. The function `ct(y)` is defined, which prints the value of `y+2`.

2. The variable `y` is first assigned the value `-6`, but then immediately reassigned the value `3`. However, these assignments have no effect on the output because `y` is not used after these lines.

3. The function `ct(y)` is called with the argument `8`. Inside the function, `y` is `8`, so `y+2` equals `10`.

4. The function prints `10`, so `10` is the output of this code.

Question

The output of the given Python code will be 10.

Here's the step by step explanation:

1. The function `ct(y)` is defined, which prints the value of `y+2`.

2. The variable `y` is first assigned the value `-6`, but then immediately reassigned the value `3`. However, these assignments have no effect on the output because `y` is not used after these lines.

3. The function `ct(y)` is called with the argument `8`. Inside the function, `y` is `8`, so `y+2` equals `10`.

4. The function prints `10`, so `10` is the output of this code.

Knowee AI · Accepted Answer

The output of the given Python code will be 10.

Here's the step by step explanation:

1. The function `ct(y)` is defined, which prints the value of `y+2`.

2. The variable `y` is first assigned the value `-6`, but then immediately reassigned the value `3`. However, these assignments have no effect on the output because `y` is not used after these lines.

3. The function `ct(y)` is called with the argument `8`. Inside the function, `y` is `8`, so `y+2` equals `10`.

4. The function prints `10`, so `10` is the output of this code.

What will be the output of the following Python code?def ct(y): print(y+2)y=-6y=3ct(8)Options10453

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