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Answer the questions below.(If necessary, consult a list of formulas.)(a) From a collection of 51 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possible?(b) A certain committee consists of 17 people. From the committee, a president, a vice-president, a secretary, and a treasurer are to be chosen. In how many ways can these 4 offices be filled? Assume that a committee member can hold at most one of these offices.

Question

Answer the questions below.(If necessary, consult a list of formulas.)(a) From a collection of 51 store customers, 3 are to be chosen to receive a special gift. How many groups of 3 customers are possible?(b) A certain committee consists of 17 people. From the committee, a president, a vice-president, a secretary, and a treasurer are to be chosen. In how many ways can these 4 offices be filled? Assume that a committee member can hold at most one of these offices.

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Solution

(a) The number of ways to choose 3 customers from a group of 51 is given by the combination formula C(n, r) = n! / [(n-r)! * r!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

In this case, n = 51 and r = 3.

So, C(51, 3) = 51! / [(51-3)! * 3!] = 51! / (48! * 3!)

This simplifies to (51 * 50 * 49) / (3 * 2 * 1) = 20825.

So, there are 20825 possible groups of 3 customers.

(b) The number of ways to fill 4 offices from a committee of 17 people is given by the permutation formula P(n, r) = n! / (n-r)!, where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

In this case, n = 17 and r = 4.

So, P(17, 4) = 17! / (17-4)! = 17! / 13!

This simplifies to (17 * 16 * 15 * 14) = 57840.

So, there are 57840 ways to fill the 4 offices.

This problem has been solved

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