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Answer the questions below.(If necessary, consult a list of formulas.)(a) 63 athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be given to the second-place finisher, and a bronze medal is to be given to the third-place finisher. Assume that there are no ties. In how many possible ways can the 3 medals be distributed?(b) A certain committee consists of 16 people. From the committee, a president, a vice-president, and a treasurer are to be chosen. In how many ways can these 3 offices be filled? Assume that a committee member can hold at most one of these offices.

Question

Answer the questions below.(If necessary, consult a list of formulas.)(a) 63 athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be given to the second-place finisher, and a bronze medal is to be given to the third-place finisher. Assume that there are no ties. In how many possible ways can the 3 medals be distributed?(b) A certain committee consists of 16 people. From the committee, a president, a vice-president, and a treasurer are to be chosen. In how many ways can these 3 offices be filled? Assume that a committee member can hold at most one of these offices.

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Solution

(a) The number of ways the 3 medals can be distributed is given by the permutation formula P(n, r) = n! / (n-r)!, where n is the total number of items, and r is the number of items to choose. Here, n = 63 (the total number of athletes), and r = 3 (the number of medals to be distributed). So, the number of ways the medals can be distributed is P(63, 3) = 63! / (63-3)! = 636261 = 238,266 ways.

(b) Similarly, the number of ways the 3 offices can be filled is given by the permutation formula P(n, r) = n! / (n-r)!, where n is the total number of items, and r is the number of items to choose. Here, n = 16 (the total number of committee members), and r = 3 (the number of offices to be filled). So, the number of ways the offices can be filled is P(16, 3) = 16! / (16-3)! = 161514 = 3,360 ways.

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