When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below.Does the mass of oxygen required equal the mass of the water formed?
Question
When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water according to the reaction below.Does the mass of oxygen required equal the mass of the water formed?
Solution
To determine if the mass of oxygen required equals the mass of water formed, we need to calculate the molar masses of oxygen and water.
The molar mass of oxygen (O2) is 32.00 g/mol (16.00 g/mol x 2).
The molar mass of water (H2O) is 18.02 g/mol (2.02 g/mol x 2 + 16.00 g/mol).
Next, we can calculate the mass of oxygen required by multiplying the number of moles of oxygen (1.50 moles) by its molar mass (32.00 g/mol):
Mass of oxygen = 1.50 moles x 32.00 g/mol = 48.00 g
Similarly, we can calculate the mass of water formed by multiplying the number of moles of water (3.00 moles) by its molar mass (18.02 g/mol):
Mass of water = 3.00 moles x 18.02 g/mol = 54.06 g
Comparing the mass of oxygen required (48.00 g) to the mass of water formed (54.06 g), we can see that the mass of oxygen is less than the mass of water. Therefore, the mass of oxygen required does not equal the mass of water formed.
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