Given the balanced chemical equation: 2 H2 + O2 --> 2 H2OWhat mass (in grams) of water would be produced from 3.00 mol of H2?You will need to calculate molar mass of water yourself.Group of answer choices54.1 g3.00 g18.02 g36.04 g
Question
Given the balanced chemical equation: 2 H2 + O2 --> 2 H2OWhat mass (in grams) of water would be produced from 3.00 mol of H2?You will need to calculate molar mass of water yourself.Group of answer choices54.1 g3.00 g18.02 g36.04 g
Solution
To solve this problem, we need to use the stoichiometry of the balanced chemical equation and the molar mass of water.
Step 1: Determine the stoichiometry. From the balanced chemical equation, we can see that 2 moles of H2 produce 2 moles of H2O.
Step 2: Calculate the molar mass of water (H2O). The molar mass of hydrogen (H) is approximately 1.01 g/mol and the molar mass of oxygen (O) is approximately 16.00 g/mol. Since water consists of 2 hydrogen atoms and 1 oxygen atom, its molar mass is (21.01 g/mol) + (116.00 g/mol) = 18.02 g/mol.
Step 3: Use the stoichiometry and the molar mass to find the mass of water produced. Since 2 moles of H2 produce 2 moles of H2O, 3.00 moles of H2 will produce 3.00 moles of H2O. Therefore, the mass of water produced is (3.00 moles of H2O) * (18.02 g/mol of H2O) = 54.06 g of H2O.
So, the answer is 54.1 g of water would be produced from 3.00 mol of H2.
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