In C, what does the expression arr[2] + arr[4] represent for the array "arr"?

What is the output of the following code?#include <stdio.h>int main() {    int arr[2][2] = {{1, 2}, {3, 4}};    printf("%d\n", arr[0][2]);    return 0;}

What is the output of the following code?#include <stdio.h>void modifyArray(int arr[], int size) {    for (int i = 0; i < size; i++) {        arr[i] = arr[i] * 2;    }}int main() {    int arr[] = {1, 2, 3, 4, 5};    int size = sizeof(arr) / sizeof(arr[0]);    modifyArray(arr, size);    printf("%d\n", arr[2]);    return 0;}

What is the output of the following code?int arr[5] = {1, 2, 3, 4, 5};int *p = arr;printf("%d\n", p[2]);

What does the line "void *ptr = arr;" do?123456789101112#include <stdio.h>int main() { int arr[2] = {10, 20},i=0; void *ptr = arr; while(i<2) { printf("%d ", *((int *)ptr + i)); i++; } return 0;}Marks : 1Negative Marks : 0Answer hereModifies the values of the array arr.Initializes a void pointer to the array arr.Prints the memory addresses of the array arr.Results in a compilation error.ClearPrev

Below is an array declaration in 'C' language:int ar1[] = {2,9};int ar2[3] = {9};What will be the output of the following print statement?printf("%d,%d", ar1[1], ar2[2]);(1 Point)