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What is the output of the following code?#include <stdio.h>void modifyArray(int arr[], int size) {    for (int i = 0; i < size; i++) {        arr[i] = arr[i] * 2;    }}int main() {    int arr[] = {1, 2, 3, 4, 5};    int size = sizeof(arr) / sizeof(arr[0]);    modifyArray(arr, size);    printf("%d\n", arr[2]);    return 0;}

Question

What is the output of the following code?#include <stdio.h>void modifyArray(int arr[], int size) {    for (int i = 0; i < size; i++) {        arr[i] = arr[i] * 2;    }}int main() {    int arr[] = {1, 2, 3, 4, 5};    int size = sizeof(arr) / sizeof(arr[0]);    modifyArray(arr, size);    printf("%d\n", arr[2]);    return 0;}

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Solution

The output of the code will be 6.

Here's the step by step explanation:

  1. An array arr is declared in the `main

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