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Box A contains 5 red and 4 blue balls, Box Bcontains 2 red and 5 blue balls. A ball is drawnat random from each box. Find the probabilitythat one is red and the other is blue.

Question

Box A contains 5 red and 4 blue balls, Box Bcontains 2 red and 5 blue balls. A ball is drawnat random from each box. Find the probabilitythat one is red and the other is blue.

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Solution

To find the probability that one ball is red and the other is blue, we need to consider the possible outcomes when drawing a ball from each box.

Let's start by calculating the total number of possible outcomes. In Box A, there are 5 red balls and 4 blue balls, so there are a total of 9 balls. In Box B, there are 2 red balls and 5 blue balls, so there are a total of 7 balls.

The total number of possible outcomes is the product of the number of balls in each box: 9 * 7 = 63.

Now, let's calculate the number of favorable outcomes, which is the number of outcomes where one ball is red and the other is blue.

From Box A, there are 5 red balls and 4 blue balls. If we draw a red ball from Box A, there are 2 red balls and 5 blue balls left in Box B. So, the number of favorable outcomes when drawing a red ball from Box A is 5 * 5 = 25.

Similarly, if we draw a blue ball from Box A, there are 4 red balls and 5 blue balls left in Box B. So, the number of favorable outcomes when drawing a blue ball from Box A is 4 * 5 = 20.

The total number of favorable outcomes is the sum of the favorable outcomes for each case: 25 + 20 = 45.

Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes: 45 / 63 = 0.7143 (rounded to four decimal places).

Therefore, the probability that one ball is red and the other is blue is approximately 0.7143.

This problem has been solved

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