A bag contains 5 red, 3 green, and 5 black balls. A ball is drawn at random from the bag. Find the probability that the ball is "not red"
Question
A bag contains 5 red, 3 green, and 5 black balls. A ball is drawn at random from the bag. Find the probability that the ball is "not red"
Solution
Sure, here's how you can solve this problem:
Step 1: First, you need to find the total number of balls in the bag. This is done by adding the number of red, green, and black balls together. So, 5 (red) + 3 (green) + 5 (black) = 13 balls in total.
Step 2: Next, you need to find the total number of balls that are not red. Since there are 5 red balls, this means there are 13 (total) - 5 (red) = 8 balls that are not red.
Step 3: The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes. In this case, the favorable outcome is drawing a ball that is not red, and the total number of outcomes is the total number of balls.
So, the probability that the ball drawn is not red is 8 (not red) / 13 (total) = 0.615 (approximately), or 61.5% when expressed as a percentage.
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