Sure, here is a simple Java code that sorts an integer list and finds the pair that adds up to a given number. This code uses the two-pointer technique after sorting the array.

```java
import java.util.Arrays;

public class Main {
public static void main(String[] args) {
int[] numbers = {10, 15, 3, 7};
int target = 17;
Arrays.sort(numbers);
int left = 0;
int right = numbers.length - 1;
while (left

Question

Sure, here is a simple Java code that sorts an integer list and finds the pair that adds up to a given number. This code uses the two-pointer technique after sorting the array.

```java
import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] numbers = {10, 15, 3, 7};
        int target = 17;
        Arrays.sort(numbers);
        int left = 0;
        int right = numbers.length - 1;
        while (left < right) {
            int sum = numbers[left] + numbers[right];
            if (sum == target) {
                System.out.println("Pair found: " + numbers[left] + ", " + numbers[right]);
                return;
            } else if (sum < target) {
                left++;
            } else {
                right--;
            }
        }
        System.out.println("No pair found");
    }
}
```

This code first sorts the array, then it uses two pointers, one at the beginning of the array and one at the end. It calculates the sum of the numbers at the two pointers. If the sum is equal to the target, it prints the pair and returns. If the sum is less than the target, it moves the left pointer one step to the right. If the sum is greater than the target, it moves the right pointer one step to the left. It continues this process until it finds a pair or the two pointers meet. If no pair is found, it prints "No pair found".

Knowee AI · Accepted Answer

Sure, here is a simple Java code that sorts an integer list and finds the pair that adds up to a given number. This code uses the two-pointer technique after sorting the array.

```java
import java.util.Arrays;

public class Main {
    public static void main(String[] args) {
        int[] numbers = {10, 15, 3, 7};
        int target = 17;
        Arrays.sort(numbers);
        int left = 0;
        int right = numbers.length - 1;
        while (left < right) {
            int sum = numbers[left] + numbers[right];
            if (sum == target) {
                System.out.println("Pair found: " + numbers[left] + ", " + numbers[right]);
                return;
            } else if (sum < target) {
                left++;
            } else {
                right--;
            }
        }
        System.out.println("No pair found");
    }
}
```

This code first sorts the array, then it uses two pointers, one at the beginning of the array and one at the end. It calculates the sum of the numbers at the two pointers. If the sum is equal to the target, it prints the pair and returns. If the sum is less than the target, it moves the left pointer one step to the right. If the sum is greater than the target, it moves the right pointer one step to the left. It continues this process until it finds a pair or the two pointers meet. If no pair is found, it prints "No pair found".

answer this question in simple code for beginners using intellJ: Sort an integer list, then find the pair that adds up to the given number

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