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Analyze the code for compile time errors. You are provided with the code skeleton having the full solution with compile time errors. Fix the compile time error in the code.Write a Java program to read an array of integer elements. The program should find the difference between the alternate numbers in the array and find the index position of the smallest element with the largest difference. If more than one pair has the same largest difference, consider the first occurrence.Note: When taking the difference, take the absolute value, i.e. neglecting the sign.Example: If it is 3 - 10= -7, consider it as 7.If the array size is less than 3, Display "Invalid array size".Note:In the Sample Input / Output provided, the highlighted text in bold corresponds to the input given by the user, and the rest of the text represents the output.Ensure to follow the object-oriented specifications provided in the question description.Ensure to provide the names for classes, attributes, and methods as specified in the question description.Adhere to the code template, if provided.Please do not use System.exit(0) to terminate the program.Sample Input/Output 1:Enter the size of the array6Enter the inputs43210861Explanation :Here alternate number difference means4-2, 3-10, 2-8, 10-6Neglect the sign So diff is 2,7,6,4Largest diff is 7 -------> 3-10, here the smallest number is 3 and its index is 1. Hence the output is 1.Sample Input/Output 2:Enter the size of the array7Enter the inputs76223182Sample Input/Output 3:-1Invalid array size

Question

Analyze the code for compile time errors. You are provided with the code skeleton having the full solution with compile time errors. Fix the compile time error in the code.Write a Java program to read an array of integer elements. The program should find the difference between the alternate numbers in the array and find the index position of the smallest element with the largest difference. If more than one pair has the same largest difference, consider the first occurrence.Note: When taking the difference, take the absolute value, i.e. neglecting the sign.Example: If it is 3 - 10= -7, consider it as 7.If the array size is less than 3, Display "Invalid array size".Note:In the Sample Input / Output provided, the highlighted text in bold corresponds to the input given by the user, and the rest of the text represents the output.Ensure to follow the object-oriented specifications provided in the question description.Ensure to provide the names for classes, attributes, and methods as specified in the question description.Adhere to the code template, if provided.Please do not use System.exit(0) to terminate the program.Sample Input/Output 1:Enter the size of the array6Enter the inputs43210861Explanation :Here alternate number difference means4-2, 3-10, 2-8, 10-6Neglect the sign So diff is 2,7,6,4Largest diff is 7 -------> 3-10, here the smallest number is 3 and its index is 1. Hence the output is 1.Sample Input/Output 2:Enter the size of the array7Enter the inputs76223182Sample Input/Output 3:-1Invalid array size

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Solution

The problem is asking to write a Java program that reads an array of integers. The program should find the difference between alternate numbers in the array and find the index position of the smallest element with the largest difference. If the array size is less than 3, the program should display "Invalid array size".

Here is a step by step solution:

  1. First, we need to import the Scanner class to read the input from the user.
import java.util.Scanner;
  1. Create a main method to run the program.
public static void main(String[] args) {
  1. Inside the main method, create a Scanner object to read the input.
Scanner sc = new Scanner(System.in);
  1. Read the size of the array.
System.out.println("Enter the size of the array");
int size = sc.nextInt();
  1. Check if the size of the array is less than 3. If it is, print "Invalid array size" and return.
if(size < 3) {
    System.out.println("Invalid array size");
    return;
}
  1. Otherwise, create an array and read the elements.
System.out.println("Enter the inputs");
int[] arr = new int[size];
for(int i = 0; i < size; i++) {
    arr[i] = sc.nextInt();
}
  1. Initialize variables to keep track of the smallest element with the largest difference and its index.
int minElement = Integer.MAX_VALUE;
int minIndex = -1;
int maxDiff = Integer.MIN_VALUE;
  1. Iterate over the array, calculate the difference between alternate numbers, and update the variables accordingly.
for(int i = 0; i < size - 2; i += 2) {
    int diff = Math.abs(arr[i] - arr[i+2]);
    if(diff > maxDiff || (diff == maxDiff && arr[i] < minElement)) {
        maxDiff = diff;
        minElement = arr[i];
        minIndex = i;
    }
}
  1. Finally, print the index of the smallest element with the largest difference.
System.out.println(minIndex);
  1. Close the Scanner object.
sc.close();
  1. Close the main method and the class.
}

Here is the complete code:

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the size of the array");
        int size = sc.nextInt();
        if(size < 3) {
            System.out.println("Invalid array size");
            return;
        }
        System.out.println("Enter the inputs");
        int[] arr = new int[size];
        for(int i = 0; i < size; i++) {
            arr[i] = sc.nextInt();
        }
        int minElement = Integer.MAX_VALUE;
        int minIndex = -1;
        int maxDiff = Integer.MIN_VALUE;
        for(int i = 0; i < size - 2; i += 2) {
            int diff = Math.abs(arr[i] - arr[i+2]);
            if(diff > maxDiff || (diff == maxDiff && arr[i] < minElement)) {
                maxDiff = diff;
                minElement = arr[i];
                minIndex = i;
            }
        }
        System.out.println(minIndex);
        sc.close();
    }
}

This problem has been solved

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