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List comprehensions can be baffling verging on incomprehensible at first (joke!), so let's get some experience pulling a list comprehension apart into code that you are more familiar with. Given the following mystery function, write an equivalent function aha(minval, maxval) with the exact same functionality but which doesn't make use of list comprehensions.def mystery(minval, maxval): return [i**2 % 10 for i in range(minval, maxval + 1)]For example:>>> aha(3, 7)[9, 6, 5, 6, 9]>>> aha(0, 10)[0, 1, 4, 9, 6, 5, 6, 9, 4, 1, 0]

Question

List comprehensions can be baffling verging on incomprehensible at first (joke!), so let's get some experience pulling a list comprehension apart into code that you are more familiar with. Given the following mystery function, write an equivalent function aha(minval, maxval) with the exact same functionality but which doesn't make use of list comprehensions.def mystery(minval, maxval): return [i**2 % 10 for i in range(minval, maxval + 1)]For example:>>> aha(3, 7)[9, 6, 5, 6, 9]>>> aha(0, 10)[0, 1, 4, 9, 6, 5, 6, 9, 4, 1, 0]

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Solution

Sure, here is the equivalent function aha(minval, maxval) without using list comprehensions:

def aha(minval, maxval):
    result = []
    for i in range(minval, maxval + 1):
        result.append(i**2 % 10)
    return result

This function works exactly the same as the mystery(minval, maxval) function. It iterates over the range from minval to maxval (inclusive), squares each number, takes the modulus 10 of the result, and appends it to the result list. Finally, it returns the result list.

This problem has been solved

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