You dissolve 4.83 g of sodium chloride in 500 mL of water, what is the molarity of sodium cations in the solution as moles per litre? Give your answer to two decimal places.

To calculate the molarity of sodium cations in the solution, we need to follow these steps:

1. First, we need to convert the mass of sodium chloride (NaCl) into moles. The molar mass of NaCl is approximately 58.44 g/mol. So, the number of moles of NaCl is 4.83 g / 58.44 g/mol = 0.0827 mol.

2. Since each NaCl molecule dissociates into one sodium cation (Na+) and one chloride anion (Cl-) in water, the number of moles of Na+ is also 0.0827 mol.

3. Next, we need to convert the volume of the solution from milliliters to liters. 500 mL = 0.5 L.

4. Finally, we calculate the molarity (M) of the solution by dividing the number of moles of Na+ by the volume of the solution in liters. M = 0.0827 mol / 0.5 L = 0.1654 M.

So, the molarity of sodium cations in the solution is 0.1654 M, or to two decimal places, 0.17 M.