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1. Transformer Per-Unit AnalysisA power system consists of a generator rated at 500 MVA, 20 kV, and a transformer rated at500 MVA, 20/230 kV with an impedance of 0.01 + j0.05 per unit on its own base. Thetransformer is connected to a transmission line with an impedance of 0.02 + j0.1 per unit ona 230 kV, 500 MVA base.a. Convert the transformer impedance to the generator base.b. Calculate the per-unit impedance of the transmission line on the generator base.c. Determine the total impedance of the system (generator, transformer, and transmissionline) in per-unit on the generator base.

Question

  1. Transformer Per-Unit AnalysisA power system consists of a generator rated at 500 MVA, 20 kV, and a transformer rated at500 MVA, 20/230 kV with an impedance of 0.01 + j0.05 per unit on its own base. Thetransformer is connected to a transmission line with an impedance of 0.02 + j0.1 per unit ona 230 kV, 500 MVA base.a. Convert the transformer impedance to the generator base.b. Calculate the per-unit impedance of the transmission line on the generator base.c. Determine the total impedance of the system (generator, transformer, and transmissionline) in per-unit on the generator base.
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Solution

a. Convert the transformer impedance to the generator base.

The transformer impedance is given as 0.01 + j0.05 per unit on its own base of 500 MVA, 20/230 kV. To convert this to the generator base of 500 MVA, 20 kV, we need to use the per unit system conversion formula:

Z_new = Z_old * (V_new/V_old)^2 * (S_old/S_new)

However, since the MVA base (S) is the same for both the transformer and the generator, the formula simplifies to:

Z_new = Z_old * (V_new/V_old)^2

The voltage ratio (V_new/V_old) is the ratio of the generator voltage to the transformer voltage, which is 20/230. Therefore, the transformer impedance on the generator base is:

Z_new = (0.01 + j0.05) * (20/230)^2 = 0.000076 + j0.00038 per unit.

b. Calculate the per-unit impedance of the transmission line on the generator base.

The transmission line impedance is given as 0.02 + j0.1 per unit on a 230 kV, 500 MVA base. To convert this to the generator base of 500 MVA, 20 kV, we use the same formula as above:

Z_new = Z_old * (V_new/V_old)^2

Therefore, the transmission line impedance on the generator base is:

Z_new = (0.02 + j0.1) * (20/230)^2 = 0.000304 + j0.00152 per unit.

c. Determine the total impedance of the system (generator, transformer, and transmission line) in per-unit on the generator base.

The total impedance of the system is the sum of the individual impedances. Therefore, the total impedance on the generator base is:

Z_total = Z_generator + Z_transformer_new + Z_transmission_new

Assuming the generator impedance is zero (since it's not given), the total impedance is:

Z_total = 0 + (0.000076 + j0.00038) + (0.000304 + j0.00152) = 0.00038 + j0.0019 per unit.

This problem has been solved

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