5. Transformer ConnectionA power system includes two transformers: T1 (100 MVA, 110/11 kV, impedance 0.05 pu)and T2 (100 MVA, 11/0.4 kV, impedance 0.06 pu). They are connected in series, with T1stepping down from 110 kV to 11 kV and T2 stepping down from 11 kV to 0.4 kV.a. Determine the per-unit impedance of each transformer on a common base of 100 MVA, 11kV.b. Find the equivalent per-unit impedance of the combined transformer system.c. Calculate the actual impedance in ohms on the 0.4 kV side
Question
- Transformer ConnectionA power system includes two transformers: T1 (100 MVA, 110/11 kV, impedance 0.05 pu)and T2 (100 MVA, 11/0.4 kV, impedance 0.06 pu). They are connected in series, with T1stepping down from 110 kV to 11 kV and T2 stepping down from 11 kV to 0.4 kV.a. Determine the per-unit impedance of each transformer on a common base of 100 MVA, 11kV.b. Find the equivalent per-unit impedance of the combined transformer system.c. Calculate the actual impedance in ohms on the 0.4 kV side
Solution
a. The per-unit impedance of each transformer on a common base of 100 MVA, 11kV:
For T1, the base impedance (Zbase1) is Vbase1^2 / Sbase1 = (11kV)^2 / 100MVA = 1.21 ohms. Therefore, the actual impedance (Z1) is Zbase1 * pu impedance = 1.21 ohms * 0.05 = 0.0605 ohms.
For T2, the base impedance (Zbase2) is Vbase2^2 / Sbase2 = (11kV)^2 / 100MVA = 1.21 ohms. Therefore, the actual impedance (Z2) is Zbase2 * pu impedance = 1.21 ohms * 0.06 = 0.0726 ohms.
b. The equivalent per-unit impedance of the combined transformer system:
The transformers are connected in series, so their impedances add up. The total actual impedance (Ztotal) is Z1 + Z2 = 0.0605 ohms + 0.0726 ohms = 0.1331 ohms.
To convert this back to per-unit, we divide by the base impedance: Ztotal (pu) = Ztotal / Zbase = 0.1331 ohms / 1.21 ohms = 0.11 pu.
c. The actual impedance in ohms on the 0.4 kV side:
To find this, we need to change the base voltage to 0.4 kV. The new base impedance (Zbase_new) is Vbase_new^2 / Sbase = (0.4kV)^2 / 100MVA = 0.0016 ohms.
The actual impedance on the 0.4 kV side is then Ztotal * Zbase_new / Zbase = 0.1331 ohms * 0.0016 ohms / 1.21 ohms = 0.000176 ohms.
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